Taking a closer look at LHC

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KINEMATICS

Eeach bunch travels at almost the speed of light (v = 0,999999991·c ) :

v = 0,999999991 x 299792458 ⇒ v = 299792455 m/s

So each one will go around

299792455 / 26659 = 11245 laps per second

So, the Frequency of the circular movement already calculated is: f = 11,245 KHz

And the Period is: T = 1/f ≈ 9·10^-5 s

Protons will be accelerated to v~c. While travelling they will permanently be under a centripetal acceleration produced by Lorentz Force.

Let´s calculate this centripetal acceleration:

a ≈ c²/r ⇒ a_c ≈ 2.3·10¹³ m/s²

Therefore 2·10¹²times the acceleration of gravity.

It's been said before that the distance between the two bunches will be : d = 7, 48 m

So the “time between bunches” -bunch spacing- will be

t = distance / velocity
t = 7,48 / 3·10⁸

t = 24,95·10^-9s ⇒ t = 24,95 ns

which is a very important parameter.

Another interesting exercise is to calculate how many laps the protons travel before falling due to gravity.

h = ½g·t² ⇒ t = (2h/g)^1/2

where h is the pipe radius (~ 28 mm)

so: t = (2·0,028/9,81)^1/2
t ≈ 76 ms

Divided by the period:

nº of laps = 76·10^-3/8,9·10^-5

n = 850 laps

Therefore, we must not only correct the electromagnetic alterations but we must also correct those due to gravity. The magnetic multipoles will correct those alterations.

	KINEMATICS
	FORCES
	MOMENTUM
	ENERGY
	LOW TEMPERATURE
	MAGNETISM
	ELECTRICITY
	SUPERCONDUCTIVITY
	LUMINOSITY
	CROSS SECTION
	RELATIVITY
	SYNCHROTRON RADIATION
	IONIZING RADIATION
	BLACK HOLES?

Eeach bunch travels at almost the speed of light (v = 0,999999991·c ) : v = 0,999999991 x 299792458 ⇒ v = 299792455 m/s So each one will go around 299792455 / 26659 = 11245 laps per second So, the Frequency of the circular movement already calculated is: f = 11,245 KHz And the Period is: T = 1/f ≈ 9·10^-5 s
Protons will be accelerated to v~c. While travelling they will permanently be under a centripetal acceleration produced by Lorentz Force. Let´s calculate this centripetal acceleration: a ≈ c²/r ⇒ a_c ≈ 2.3·10¹³ m/s² Therefore 2·10¹²times the acceleration of gravity.

It's been said before that the distance between the two bunches will be : d = 7, 48 m So the “time between bunches” -bunch spacing- will be t = distance / velocity t = 7,48 / 3·10⁸ t = 24,95·10^-9s ⇒ t = 24,95 ns which is a very important parameter.

Another interesting exercise is to calculate how many laps the protons travel before falling due to gravity.
h = ½g·t² ⇒ t = (2h/g)^1/2 where h is the pipe radius (~ 28 mm) so: t = (2·0,028/9,81)^1/2 t ≈ 76 ms Divided by the period: nº of laps = 76·10^-3/8,9·10^-5 n = 850 laps
Therefore, we must not only correct the electromagnetic alterations but we must also correct those due to gravity. The magnetic multipoles will correct those alterations.